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6r^2-72r+120=0
a = 6; b = -72; c = +120;
Δ = b2-4ac
Δ = -722-4·6·120
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-72)-48}{2*6}=\frac{24}{12} =2 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-72)+48}{2*6}=\frac{120}{12} =10 $
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